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Q. A concave lens of focal length $20 \, cm$ product an image half in size of the real object. The distance of the real object is

NTA AbhyasNTA Abhyas 2022Ray Optics and Optical Instruments

Solution:

We know that
$m=\frac{f}{f + u}$
$\frac{1}{2}=\frac{- 20}{- 20 + u} \, or-20+u=-40$
Or $ \, u=-40+20 \, $ or $ \, \, u=-20 \, cm$