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Q.
A compound with haemoglobin like structure contains one atom of iron per molecule. If it contains 4.6 % iron, its approximate molecular mass is
Some Basic Concepts of Chemistry
Solution:
If $4.6$ of $Fe$ is present mass of compound $=100\,g$
If $56$ a.m.u. of $Fe$ is present mass of compound
$=\frac{100}{46} \times56$ a.m.u
$=1217.39$ a.m.u.
Molar mass of compound $=1217.39\,g\,mol^{-1}$