Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A compound $M_{p}X_{q}$ has cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is
image

The Solid State

Solution:

Contribution by $8 \,X$ atoms present at the corners
$=\frac{1}{8} \times 8=1$
Contribution by $6\, X$ atoms present at the face centres
$=6 \times \frac{1}{2}=3$
Total $X$ atoms $= 3 + 1 = 4$
Contribution by $4 \,M$ atoms present at edge centres
$=4 \times \frac{1}{4} = 1$
$1 \,M$ atom present at body centre contributes completely to $1 $ unit cell
Thus, total $M$ atoms in one unit cell $= 1 + 1 = 2 $
Ratio is $M :X =2:4=1:2$
Thus, empirical formula is $MX_{2}$