1. Tardigrade
  2. Question
  3. Chemistry
  4. A compound is formed by cation C and anion A. The anions form hexagonal close packed (hep) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

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Q. A compound is formed by cation C and anion A. The anions form hexagonal close packed (hep) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

NEETNEET 2019The Solid State

Solution:

$ \bullet$ Anions(A) are in hcp, so number of anions (A) = 6
Cations(C) are in 75% O.V., so number of cations (C)
$ = 6 \times \frac{3}{4}$
$ = \frac{18}{4}$
$ = \frac{9}{2}$
$\bullet$ So formula of compound will be
$C_{\frac{9}{2} } A_6 \Rightarrow \; C_9A_{12}$
$C_9 A_{12} \Rightarrow C_3A_4$