Q. A compound contains $38.8\% C, 16\%$ H and $45.2\% N$. The empirical formula of the compound will be:
Bihar CECEBihar CECE 2002Some Basic Concepts of Chemistry
Solution:
Element
%
Relative no. of atoms
Simple ratio
C
38.8
38.8/12=3.2
3.2/3.2=1
H
16.0
16/1=16.0
16.0/3.2=5
N
45.2
45.2/14=3.2
3.2/3.2=1
$\therefore $ Empirical formula $= CH _{5} N$
| Element | % | Relative no. of atoms | Simple ratio |
|---|---|---|---|
| C | 38.8 | 38.8/12=3.2 | 3.2/3.2=1 |
| H | 16.0 | 16/1=16.0 | 16.0/3.2=5 |
| N | 45.2 | 45.2/14=3.2 | 3.2/3.2=1 |