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Q. A compound 'A' when treated with $HNO_3$(in presence of $H_2SO_4)$ gives compound which is then reduced with $Sn$ and $HCl$ to aniline ? The compound A is

Amines

Solution:

$\underset{\text{Benzene (A)}}{{C_{6}H_{6}}}\xrightarrow{HNO_{3}+H_{2}SO_{4} } \underset{\text{Nitrobenzene (B)}}{{C_{6}H_{5}NO_{2}}}\xrightarrow{Sn/HCl } \underset{\text{Aniline(C)}}{{C_{6}H_{5}NH_{2}}}$