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  4. A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input resistance is 1 k Ω and load is 10 k Ω. The voltage gain will be

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Q. A common emitter amplifier is designed with $n-p-n$ transistor $(\alpha=0.99)$. The input resistance is $1\, k\, \Omega$ and load is $10 \,k \,\Omega$. The voltage gain will be

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$\beta=\frac{\alpha}{1-\alpha}=99$
$V_{\text {gain }}=\beta \frac{R_{\text {out }}}{R_{\text {in }}}$
$=99 \times \frac{10}{1}=990$