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  4. A coil resistance 20 Ω and inductance 5 H is connected with a 100 V battery. Energy stored in the coil will be

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Q. A coil resistance $20\, \Omega$ and inductance $5\, H$ is connected with a $100\, V$ battery. Energy stored in the coil will be

Electromagnetic Induction

Solution:

$U=\frac{1}{2} L i^{2}$
$=\frac{1}{2} L\left(\frac{E}{R}\right)^{2}$
$=\frac{1}{2} \times 5 \times\left(\frac{100}{20}\right)^{2}$
$=62.50\, J$