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  4. A coil of wire of certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a second similar coil of 500 turns will be

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Q. A coil of wire of certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a second similar coil of 500 turns will be

Electromagnetic Induction

Solution:

Inductance, L $\propto$ N$^2$
$\therefore $ Inductance of similar coil of different turns is given by L' = L $\frac{N'^2}{N^2} = 108 \times \left( \frac{500}{6000} \right)^2 $ = 75 m H