Question

A coil of resistance $300 \Omega$ and inductance $1 H$ is connected across an alternating voltage of frequency $300 / 2 \pi Hz$. Calculate the phase difference between voltage and current in the circuit.

• A. $60^{\circ}$
• B. $30^{\circ}$
• C. $45^{\circ}$
• D. $90^{\circ}$

Answer 1

Answer: (C)

$R ^{\prime}=300 \Omega, \quad L =1 H , \, v=\frac{300}{2 \pi} Hz$
$\therefore \tan \phi=\frac{X_{L}}{R}$
$\Rightarrow \frac{2 \pi v L}{R}$
$\therefore \tan \phi=\frac{2 \pi \times \frac{300}{2 \pi} \times 1}{300}=1$
$\phi=45^{0}$