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Physics
A coil having N turns carry a current as shown in the figure. The magnetic field intensity at point P is:
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Q. A coil having $N$ turns carry a current as shown in the figure. The magnetic field intensity at point $P$ is:
JIPMER
JIPMER 2005
Moving Charges and Magnetism
A
$\frac{\mu_{0} N i R^{2}}{2\left(R^{2}+x^{2}\right)^{3 / 2}}$
95%
B
$\frac{\mu_{0} N i}{2 R}$
5%
C
$\frac{\mu_{0} N i R^{2}}{(R+x)^{2}}$
0%
D
zero
0%
Solution:
From the formula, magnetic field intensity at point $P$, shown in given figure while coil carry current $i$ and having $N$ turns is given by
$\frac{\mu_{0} N i R^{2}}{2\left(R^{2}+x^{2}\right)^{3 / 2}}$