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Q. A closely wound coil of $ 100$ turns and area of crosssection $1 cm ^{2}$ has a coefficient of self-induction $1 mH$. The magnetic induction in the centre of the core of the coil when a current of $2 A$ flows in it, will be:

Electromagnetic Induction

Solution:

$B =\frac{\mu_{0} Ni }{2r}$
$=\frac{4 \pi \times 10^{-7} \times 100 \times 2 \times \sqrt{\pi}}{2 \times 10^{-2}}$
$=0.002\, Wb / m ^{2}$