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Physics
A closed organ pipe of length 1.2 m vibrates in its first overtone mode. The pressure variation is maximum at
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Q. A closed organ pipe of length $1.2 \,m$ vibrates in its first overtone mode. The pressure variation is maximum at
AIIMS
AIIMS 2009
A
0.4 m from the open end
B
0.4 m from the closed end
C
Both (a) and (b)
D
0.8 m from the open end
Solution:
In first overtone mode
$l =\frac{3 \lambda}{4}$
$\therefore \frac{\lambda}{4} =\frac{l}{3}$
$=\frac{1.2}{3}=0.4 \,m$
Pressure variation will be maximum at displacement nodes, ie, at $0.4\, m$ from the open end.