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Q.
A circular wire of radius 3 cm is cut and bent so as to lie along the circumference at a loop whose radius is 48 cm. The angle in grades which is subtended at the centre of the loop is
Solution:
Circumference of a circle of radius = 3 cm
= 2$\pi$ (3) = 6$\pi$ cm.
$\therefore $ length of the wire $(l)$ = 6 $\pi$ cm
Radius $(r)$ = 48 cm
Since $\theta = \frac{l}{r} = \frac{6 \pi}{48} = \frac{\pi}{8}$ Radians = $\frac{200}{8}$ grades