1. Tardigrade
  2. Question
  3. Physics
  4. A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc (. in . kg m 2)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A circular thin disc of mass $2 \,kg$ has a diameter $0.2 \,m$. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc $\left(\right.$ in $\left. kg m ^{2}\right)$

System of Particles and Rotational Motion

Solution:

$I=\frac{M R^{2}}{2}$
About axis passing through edge, moment of inertia $=I^{\prime}$
$\therefore I^{\prime}=I+M R^{2} \quad$ (By theorem of parallel axes)
or $ I^{\prime}=\frac{M R^{2}}{2}+M R^{2}=\frac{3}{2} M R^{2}=\frac{3}{2} \times 2 \times(0.1)^{2}$
or $ I^{\prime}=0.03\, kg\, m ^{2}$