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Q. A circular metal plate has radius $2.0\, m$ and negligible thickness. It is given a charge $40\, mC$. electric field at a point close to the plate and near its centre is nearest to

Electrostatic Potential and Capacitance

Solution:

$E = \sigma /\varepsilon_0$ and $\sigma = q/ \pi \, r^2$ . Hence $E = q / \pi\, \varepsilon_0 \, r^2$