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  4. A circular disc of radius r = 5 m is rotating in horizontal plane about y-axis. Y-axis is vertical axis passing through the centre of disc and x-z is the horizontal plane at ground. The height of disc above ground is h = 5 m. Small particles are ejecting from disc in horizontal direction with speed 12 m/s from the circumference of disc then the distance of these particles from origin when they hits the x-z plane is

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Q. A circular disc of radius $r = 5\,m$ is rotating in horizontal plane about y-axis. Y-axis is vertical axis passing through the centre of disc and x-z is the horizontal plane at ground. The height of disc above ground is $h = 5\,m$. Small particles are ejecting from disc in horizontal direction with speed $12 m/s$ from the circumference of disc then the distance of these particles from origin when they hits the x-z plane is

Motion in a Plane

Solution:

$R = u \sqrt{\frac{2 h }{ g }}=12$
$\sqrt{\frac{10}{10}}=12 m$
$\therefore S =\sqrt{ R ^{2}+ r ^{2}}=13 m$