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  4. A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction (1/p)(Wb/m2) in such a way that its axis makes an angle of 60° with vecB. The magnetic flux (in Wb) linked with the disc is:

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Q. A circular disc of radius $0.2$ meter is placed in a uniform magnetic field of induction $\frac{1}{p}\left(Wb/m^{2}\right)$ in such a way that its axis makes an angle of $60^{\circ}$ with $\vec{B}$. The magnetic flux (in Wb) linked with the disc is:

Electromagnetic Induction

Solution:

Here, $B=\frac{1}{p}\left(Wb/m^{2}\right) \theta =60^{\circ}$
Area normal to the plane of the disc
$= pr^{2}$ cos $60^{\circ} = \frac{pr^{2}}{2}$
Flux $= B \times$ normal area
$= \frac{0.2 \times0.2}{2} = 0.02Wb$