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Q. A circular disc A and a ring B have same mass and same radius. If they are rotated with the same angular speed about their own axis, then

KEAMKEAM 2015

Solution:

Moment of inertia of disc
$ I _{ disc }=\frac{ MR ^{2}}{2} $
Moment of inertia of ring $I_{\text {ring }}= MR ^{2}$ Therefore, A has less moment of inertia than B because of which A has less rotational kinetic energy than $B$.