Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A circular current loop of magnetic moment is in an arbitrary orientation in an external magnetic field $B$. The work done to rotate the loop by $30^{\circ}$ about an axis perpendicular to is planers

Magnetism and Matter

Solution:

As, work done,
$W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right)=0$
(As there no change in angle between $M$ and $B$ and when loop in rotated by $30^{\circ}$)