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Q. A circular coil of 50 turns and radius $20 cm$ carries a current of $12 A .$ Find magnetic moment associated with it:

Magnetism and Matter

Solution:

$M = N I A $
$ M = N I \left(\pi R ^{2}\right)$
$=50 \times 12 \pi(0.2)^{2}$
$=50 \times 12 \times 3.14 \times 0.04$
$=75.4 Am ^{2}$