Thank you for reporting, we will resolve it shortly
Q.
A circular coil carrying a certain current produces a magnetic field $B_o$ at its centre. The coil is now rewound so as to have $3\, turns$ and the same current is passed through it. The new magnetic field at the centre is
The magnetic field produced at the centre of the circular coil carrying current is given by
$Bv = \frac{\mu_0 NI}{2r}$
For one turn$ N = 1 $
$B_0 = \frac{\mu_0 I}{2r}$
As the coil is rewound
$r' = \frac{r}{3} , N' = 3$
$B' = \frac{\mu_0I \times 3}{2 \times \left( \frac{r}{3} \right)}$
$= \frac{9 \mu_0I }{2r} = 9B_0$