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  4. A circuit is shown in the figure. The e.m.f. of the battery is

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Q. A circuit is shown in the figure. The e.m.f. of the battery isPhysics Question Image

AMUAMU 2017

Solution:

Equivalent resistance and current in the circuit has been calculated in the figures given below
In series, $R_{eq} = 1 + 1 = 2\,\Omega$image
In parallel, $R_{eq} = \frac{2\times 2}{2 + 2} = 1\,\Omega$
image
In series, $R_{eq} = 2 + 1 = 3\,\Omega$
image
In series$R_{eq} = \frac{6\times 3}{6 + 3} = 2\,\Omega$
image
In series, $R_{eq} = 2 + 2 = 4\,\Omega$
image
$\therefore $ emf, $E = $ (Total current) $\times$ (Net equivalent resistance)
$ = 3\times 4 = 12\,V$