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  4. A circuit is arranged as shown. Then the current from A to B is

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Q. A circuit is arranged as shown. Then the current from $A$ to $B$ isPhysics Question Image

Current Electricity

Solution:

$I=\frac{\sum(E / r)}{1+R \Sigma(1 / r)}$
$=\frac{\frac{5}{15}+\frac{10}{10}}{1+10\left[\frac{1}{15}+\frac{1}{10}\right]}=\frac{1}{2} A =500 \,mA$