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  4. A circuit contains an ammeter, a battery of 45 V and resistance 40.8 ohm, all connected in series. If the ammeter has a coil resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will be ampere.

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Q. A circuit contains an ammeter, a battery of $45\, V$ and resistance $40.8\, ohm$, all connected in series. If the ammeter has a coil resistance $480\, ohm$ and a shunt of $20\, ohm$, the reading in the ammeter will be _______ ampere.

Current Electricity

Solution:

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Here combination of $(480 \,\Omega || 20 \,\Omega$ ) is in series with $40.8 \,\Omega$
$ R _{\text {eff }}=40.8+\frac{480 \times 20}{480+20}$
$=40.8+19.2=60 \,\Omega $
$ I =\frac{ V _{\text {eff }}}{ R _{\text {eff }}}=\frac{45}{60}=0.75 \,A$