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Q. A circuit consists of a coil with inductance $L$ and an uncharged capacitor of capacitance $C$. The coil is in a constant uniform magnetic field such that the flux through the coil is $\phi$. At time $t=0 min$, the magnetic field is abruptly switched OFF. Let $\omega_{0}=1 / \sqrt{L C}$ and ignore the resistance of the circuit. Then,

KVPYKVPY 2019Alternating Current

Solution:

At $t = 0$ capacitor is uncharged and flux of inductor is $\phi.$
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Now, using $\phi = LI,$ at $t = 0$ current in circuit is
$I_{0}=\frac{\phi}{L}$
Instantaneous current in circuit is $\frac{dq}{dt}.$
where, $q$ is solution of
$L\frac{d^{2}\,q}{dt^{2}}+\frac{q}{C}=o$
or $\frac{d^{2}\,q}{dt^{2}}+\frac{q}{LC}=o$
At $t = 0,$ current in circuit is non-zero,
so instantaneous current is given by
$=I_{0} \cos \omega t =\frac{\phi}{L} . \cos\omega t$