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Mathematics
A circle touches both the axes and its centre lies in the fourth quadrant. If its radius is 1 then its equation will be -
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Q. A circle touches both the axes and its centre lies in the fourth quadrant. If its radius is 1 then its equation will be -
Conic Sections
A
$x^2+y^2-2 x+2 y+1=0$
B
$x^2+y^2+2 x-2 y-1=0$
C
$x^2+y^2-2 x-2 y+1=0$
D
$x^2+y^2+2 x-2 y+1=0$
Solution:
Centre $(1,-1)$
equation $(x-1)^2+(y+1)^2=1$