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Q. A chord of the parabola $y = x^2 - 2x + 5$ joins the point with the abscissas $x_1 =1, x_2 = 3$ Then the equation of the tangent to the parabola parallel to the chord is :

UPSEEUPSEE 2017

Solution:

Given equation of parabola is
$y=x^{2}-2 x+5\,...(i)$
By putting $x_{1}=1, x_{2}=3$ in Eq. (i), we get
$y_{1}=1 $ and $y_{2}=8$
$\therefore $ Points on the parabola are $(1,4)$ and $(3,8)$
Equation of the chord of given parabola by joining the points $(1,4)$ and $(3,8)$ will be
$y-4=\frac{8-4}{3-1}(x-1) $
$y-4=2 x-2 $
$\Rightarrow \, 2 x-y+2=0$
Now, equation of tangent parallel to chord will be
$2 x-y+k=0\,...(ii)$
In given options, only option (b) satisfies the condition for Eq. (iii)
i.e. $ 2 x-y+1=0\,...(iii)$