1. Tardigrade
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  3. Chemistry
  4. A chemical reaction was carried out at 300 K and 280 K . The rate constants were found to be k1 and k2 respectively. Then

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Q. A chemical reaction was carried out at $ 300\, K$ and $ 280 \,K$ . The rate constants were found to be $ k_1 $ and $ k_2 $ respectively. Then

Chemical Kinetics

Solution:

For every $10°C$ rise of temperature rate constant becomes double. Thus for $20°C$ rise $(280\, K$ to $300\, K) $ rate constant becomes four times.
$ i.e\, k_1 = 4k_2$ or $k_2 = \frac{1}{4} k_1 = 0.25\, k_1 $