Question

A charged particle of mass $3 \times 10^{-3} Kg$ and charge $6 \times 10^{-6} C$ enters in an electric field of $7 V / m$. Then its kinetic energy after $1 m$ is

• A. $10^{-4} J$
• B. $9 \times 10^{-2} J$
• C. $1.05 \times 10^{-3} J$
• D. $4.2 \times 10^{-5} J$

Answer 1

Answer: (D)

$ K . E =\Delta U $
$= q \Delta V $
$= qEd =4.2 \times 10^{-5} J $