Q. A charged particle enters a uniform magnetic field with a certain speed at right angles to it. In the magnetic field a change could occur in its
J & K CETJ & K CET 2006
Solution:
Force acting on particle due to magnetic field $B$ is
$F=q \vec{v} \times \vec{B}$...(i)
and centripetal force is $F=\frac{m v^{2}}{r}$...(ii)
From Eqs. (i) and (ii), we get
$B=\frac{m v}{r q}=\frac{\text { linear momentum }}{\text { charge }}$
