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Q. A charged particle enters a uniform magnetic field with a certain speed at right angles to it. In the magnetic field a change could occur in its

J & K CETJ & K CET 2006

Solution:

Force acting on particle due to magnetic field $B$ is
$F=q \vec{v} \times \vec{B}$...(i)
and centripetal force is $F=\frac{m v^{2}}{r}$...(ii)
From Eqs. (i) and (ii), we get
$B=\frac{m v}{r q}=\frac{\text { linear momentum }}{\text { charge }}$

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