1. Tardigrade
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  4. A charged oil drop of mass 9.75× 10-15kg and charge 30× 10-16C is suspended in a uniform electric field existing between two parallel plates. The field between the plates, taking (g=10 text ms-2) is:

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Q. A charged oil drop of mass $ 9.75\times {{10}^{-15}}kg $ and charge $ 30\times {{10}^{-16}}C $ is suspended in a uniform electric field existing between two parallel plates. The field between the plates, taking $ (g=10\text{ }m{{s}^{-2}}) $ is:

KEAMKEAM 2003

Solution:

In equilibrium $ eE=mg $ $ \Rightarrow $ $ E=\frac{mg}{e} $ $ =\frac{9.75\times {{10}^{-15}}\times 10}{30\times {{10}^{-16}}} $ $ =32.5\,V/m $