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  4. A charged oil drop of mass 9.75 × 10-15 kg and charge 30 × 10-16 C is suspended in a uniform electric field existing between two parallel plates. The field between the plates, (taking g = 10 ms-2) is

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Q. A charged oil drop of mass $9.75 \times 10^{-15}$ kg and charge $30 \times 10^{-16}$ C is suspended in a uniform electric field existing between two parallel plates. The field between the plates, (taking $g = 10\,ms^{-2}$) is

Electrostatic Potential and Capacitance

Solution:

In equilibrium,
$eE = mg$
$\Rightarrow E = \frac{mg}{e}$
$= \frac{9.75 \times 10^{-15} \times 10}{30 \times 10^{-16}}$
$= 32.5\, V/m$