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Q. A charge $Q$ is uniformly on a ring of radius $R.$ Find the electric potential on the axis of ring at distance $x$ from the centre of the ring :

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
Small potential at $P$ due to $dq$
$dV=\frac{1}{4 \pi ϵ_{0}}\cdot \frac{d q}{\sqrt{R^{2} + x^{2}}}$
$V_{P}=\Sigma dV=\frac{1}{4 \pi ϵ_{0}}\cdot \frac{\Sigma d q}{\sqrt{R^{2} + x^{2}}}$
$=\frac{1}{4 \pi ϵ_{0}}\cdot \frac{Q}{\sqrt{R^{2} + x^{2}}}$