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Q. A charge $Q$ is uniformly distributed over a large plastic plate. The electric field at a point $P$ close to the centre of the plate is $10 \,V / m$. If the plastic plate is replaced by a copper plate of the same geometrical dimensions and carrying the same charge $Q$, the electric field (in $V / m$ ) at the point $P$ will become -

Electric Charges and Fields

Solution:

For a non conducting plate
$\vec{ E }=\frac{\sigma}{2 \varepsilon_{0}} \hat{ n }=10 \,V / m$
for conducting plate of copper
$\vec{ E }=\frac{\sigma}{\varepsilon_{0}} \hat{ n }=20\, V / m$