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Q.
A charge ' $q$ ' is placed at the centre of the line joining two equal charges ' $Q$ ' The system of the three charges will be in equilibrium, if ' $q$ ' is equal to
Solution:
Consider forces on charge at '
$B$ '
For equilibrium, $F_{\text {net }}=0$
$F_{A}+F_{c}=0$
$\frac{1}{4 \pi G_{0}} \frac{Q^{2}}{x^{2}}+\frac{1}{4 \pi G_{0}} \frac{q Q}{x^{2} / 4}=0$
$Q+4 q=0$
$\therefore q=-\frac{Q}{4}$
