Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A charge q is placed at O in the cavity in a spherical uncharged conductor. Point S is outside the conductor. If the charge is displaced from O towards S, still remaining within the cavity,Physics Question Image

Electric Charges and Fields

Solution:

By Gauss's law, the electric field at $S$ is $E .4 \pi r ^{2}=\frac{ q _{ en }}{\epsilon_{0}} $
$\Rightarrow E =\frac{ q _{ en }}{4 \pi \epsilon_{0} r ^{2}}$
where $r =$ distance from center to $S .$
When we move charge q towards $S$ within cavity,
the enclosed charge $q _{ en }$ will remain same i.e, $q _{ eq }= q$.
Thus, the field at $S$ will not change.