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Q. A charge $(-q)$ and another charge $(Q)$ are kept at two points $A$ and $B$ respectively. Keeping the charge $(+Q)$ fixed at $B$, the charge $(-q)$ at $A$ is moved to another point $C$ such that $A B C$ forms an equilateral triangle of side $l$. The net work done in moving the charge $(-q)$ is

Electrostatic Potential and Capacitance

Solution:

According to figure, potential at $A$ and $C$ are equal.
Hence work done in moving $-q$ charge from $A$ to $C$ is zero.
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