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  4. A charge of 5 C experiences a force of 5000 N when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of 1 cm ?

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Q. A charge of $5\, C$ experiences a force of $5000\, N$ when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of $1\, cm ?$

Electrostatic Potential and Capacitance

Solution:

$F=Q E=\frac{Q V}{d}$
$\Rightarrow 5000 =\frac{5 \times V}{10^{-2}}$
$\Rightarrow V=10$ volt