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  4. A charge is fired through a magnetic field. The force acting on it is maximum when the direction of motion of the charge and magnetic field is :

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Q. A charge is fired through a magnetic field. The force acting on it is maximum when the direction of motion of the charge and magnetic field is :

J & K CETJ & K CET 2001

Solution:

If the charged particle is moving in a magnetic field $\vec{B}$, with a velocity $\vec{v}$ it experiances a force given by,
$\vec{F}=q(\vec{v} \times \vec{B})=$ qvB $\sin \theta$
where, $\theta$ is the angle between $v$ and $B$
If $\theta=\pi / 2$ therefore, sin $\pi / 2=1$
Hence, $F=$ qvB
The magnetic force acting on it is maximum when the angle between the direction of motion and
magnetic field is $\pi / 2$