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Q. A certain current passing through a copper voltameter deposits 0.002 kg of copper on cathode plate in 100 minutes. If there are $ {{10}^{25}} $ copper atoms in 1kg of copper, the electric charge delivered to cathode by copper ions $ (C{{u}^{2+}}) $ per second will be

AMUAMU 1999

Solution:

: Number of atoms $ =(0.002\times {{10}^{25}}) $ $ \therefore $ Charge $ =0.002\times {{10}^{25}}\times 2\times 1.6\times {{10}^{-19}} $ $ \therefore $ $ \frac{charge\text{ }delivered}{second} $ $ =\frac{0.002\times {{10}^{25}}\times 2\times 1.6\times {{10}^{-19}}}{100\times 60} $ = 1.06 C per second