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Q. A certain current liberates $0.504\, g$ hydrogen is $2$ hours. How many gram of oxygen can be liberated by the same current in the same time?

J & K CETJ & K CET 2010Electrochemistry

Solution:

Since, same amount of current is passed for same time,
$\frac{w_{H}}{w_{O}}=\frac{E_{H}}{E_{O}}$
(Here, $w$ represents mass and $E$ represents equivalent mass.)
$\frac{0.504}{w_{O}}=\frac{E_{H}}{E_{O}}$
(Here, $w$ represents mass and $E$ represents equivalent mass.)
$\frac{0.504}{w_{O}}=\frac{1.008}{8}$
$w_{O}=\frac{0.504 \times 8}{1.008}=4.0\, g$