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Q. A certain aqueous solution of $FeCl _{3}$ [formula mass $=162]$ has a density of $1.1 g / mL$ and contains $20.0 \% FeCl _{3} .$ Molar concentration of this solution is

AIIMSAIIMS 2000Solutions

Solution:

20% FeCl3 solution means 100 g of solution contains 20 g FeCl3 .
$\Rightarrow $ Volume of 100 g solution $=\frac{100\,g}{1.1\,g/mL}$
$=90.91 \,mL$
Moles of 20 g FeCl$_{3}=\frac{20}{162}=0.1234$ mole
$\Rightarrow $ Molar concentration of solution
$=\frac{0.1234}{90.91}\times1000$
$=1.357$ M