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  4. A cell of internal resistance r is connected across an external resistance nr. Then the ratio of the terminal voltage to the emf of the cell is

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Q. A cell of internal resistance $r$ is connected across an external resistance $nr$. Then the ratio of the terminal voltage to the emf of the cell is

Current Electricity

Solution:

Internal resistance $= r$,
External resistance $= nr$.
Let terminal voltage $= V$
$\text { then } V=E-I r \Rightarrow V=E-\frac{E r}{(n+1) r}$
$V=\frac{n E}{n+1} \Rightarrow \frac{V}{E}=\frac{n}{n+1}$