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Q. A cell of internal resistance $3 \Omega$ and emf 10 volt is connected to a uniform wire of length $500$ cm and resistance 3 ohm. The potential gradient in the wire is

Current Electricity

Solution:

Potential gradient $=\left(\frac{ E }{ R + r }\right) \frac{ r }{ L }$
$=\frac{10 \times 3}{(3+3) \times 5}$
$\Rightarrow \frac{30}{6 \times 5}=1 Vm ^{-1}$
$V =10 mV / cm$