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Q. A cell of emf $E$ having an internal resistance $r$ is connected to an external resistance $R$ . The potential difference $V$ across the resistance $R$ varies with $R$ as shown by the curve:
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$V=E-ir=E\frac{R + r - r}{R + r}$
$\Rightarrow V=\frac{E R}{R + r}$
$\Rightarrow \text{ V} = 0 $ at $\text{R} = 0$
and $V=E$ at $R=\infty $