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  4. A cell E 1 of emf 6 V and internal resistance 2 Ω is connected with another cell E 2 of emf 4 V and internal resistance 8 Ω (as shown in the figure). The potential difference across points X and Y is

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Q. A cell $E _{1}$ of emf $6 V$ and internal resistance $2 \Omega$ is connected with another cell $E _{2}$ of emf $4 V$ and internal resistance $8 \Omega$ (as shown in the figure). The potential difference across points $X$ and $Y$ isPhysics Question Image

JEE MainJEE Main 2021Current Electricity

Solution:

$I =\frac{6-4}{10}=\frac{1}{5} A$
$V _{ x }+4+8 \times \frac{1}{5}- V _{ y }=0$
$V _{ x }- V _{ y }=-5.6$
$ \Rightarrow | Vx - Vy |=5.6 V$