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  4. A carnot engine having an efficiency of (1/10) as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :

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Q. A carnot engine having an efficiency of $\frac{1}{10} $ as heat engine, is used as a refrigerator. If the work done on the system is $10\,J$, the amount of energy absorbed from the reservoir at lower temperature is :

NEETNEET 2017Thermodynamics

Solution:

$\beta=\frac{1-\eta}{\eta}$
$=\frac{1-\frac{1}{10}}{\frac{1}{10}}=\frac{\frac{9}{10}}{\frac{1}{10}}$
$\beta=9$
$\beta=\frac{Q_{2}}{W}$
$Q_{2}=9 \times 10=90\, J$