1. Tardigrade
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  3. Chemistry
  4. A carbonyl compound P, which gives positive iodoform test, undergoes reaction with Me Mg Br followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S. P ->[1. MeMgBr][ underset3.H2SO4, Δ2.H+, H2O] Q ->[1.O3][2.Zn, H2O] R ->[1.OH-][2.Δ] S The structure of the product S is

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Q. A carbonyl compound $P$, which gives positive iodoform test, undergoes reaction with $Me \,Mg Br$ followed by dehydration to give an olefin $Q$. Ozonolysis of $Q$ leads to a dicarbonyl compound $R$, which undergoes intramolecular aldol reaction to give predominantly $S$.
$P \ce{->[1. MeMgBr][\underset{3.H_2SO_4, \Delta}{2.H^+, H_2O}]} Q \ce{->[1.O_3][2.Zn, H_2O]} R \ce{->[1.OH^-][2.\Delta]} S$
The structure of the product $S$ is

JEE AdvancedJEE Advanced 2009

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