Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A car moving with a speed of 25 m/s takes a U-tum in 5 s, without changing its speed. The average acceleration during these 5 s is

VMMC MedicalVMMC Medical 2011

Solution:

Average acceleration $ \text{= }\frac{\text{change in velocity}}{\text{time}} $ $ =\frac{25-(-25)}{5} $ $ =10\,m/{{s}^{2}} $